Lottery Tie-Breaker Question
Moderators: Duke4life831, Marcus
Lottery Tie-Breaker Question
-
loflin3hree5ive
- Retired Mod
- Posts: 7,342
- And1: 67
- Joined: Aug 27, 2003
- Location: Clipperland
Lottery Tie-Breaker Question
If two teams end the season with the same record as it appears the Knicks and Clippers could this year, how is the tiebreaker determined? I thought it was according to the records of the head-to-head match ups between the teams, similar to playoff seedings. But I've been told it's a coin flip-type of tiebreaker. Anybody know the answer to this?
-
Spykes
- Retired Mod
- Posts: 25,738
- And1: 16
- Joined: Mar 15, 2004
- Location: Paddy's Pub
This happened with Portland and Minnesota last year.
There is a coin-toss, but it has nothing to do with how many ping-pong balls both teams get. If teams end with a tied record, their ping-pong balls are added together and split evenly. The coin-toss determines who sits in which spot on lottery day.
Going back to the Portland/Minny example, both teams tied for the 6th spot in the lottery because of their records. A coin toss was held and Portland won, thats why they ended up in the 6th spot pre-lotto and Minny was in the 7th spot. Combined, the 6 and 7 spot has a total of 106 lotto balls. They were split down the middle, Portland got the first batch of 53 and Minny got the second batch of 53.
There is a coin-toss, but it has nothing to do with how many ping-pong balls both teams get. If teams end with a tied record, their ping-pong balls are added together and split evenly. The coin-toss determines who sits in which spot on lottery day.
Going back to the Portland/Minny example, both teams tied for the 6th spot in the lottery because of their records. A coin toss was held and Portland won, thats why they ended up in the 6th spot pre-lotto and Minny was in the 7th spot. Combined, the 6 and 7 spot has a total of 106 lotto balls. They were split down the middle, Portland got the first batch of 53 and Minny got the second batch of 53.