getrichordie wrote:If the Thunder split the last two games = .611 W/L% ; if the Thunder lose the last two games = .597 W/L%
If the Jazz win their last game = .611 W/L% ; If the Jazz lose their last game = .597 W/L%
If the Pacers split their last two games = .603 W/L%; If the Pacers lose their last two games = .589 W/L% ; If Pacers win their last two games = .616 W/L%
If the 76ers win their last two games = .603 W/L% ; if the 76ers split their last two games = .589 W/L%
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So if... 76ers win their last two games + the Jazz win their last game and/or the Pacers split their last two games + the Thunder lose the last two games... our pick will not convey.
If the Thunder split the last two games + the Jazz win their last game + the Pacers win their last two games... the pick will not convey.
If the Thunder lose the last two games + the Jazz lose their last game + the Pacers split their last two games... the pick will not convey.
If the Thunder lose their 2 remaining games, and the Jazz lose their remaining game against the Spurs, then the Jazz and Thunder would be tied in the W/L column. OKC would get the #5 seed due to holding the tie-breaker. However, there would likely be a coin-toss to determine the draft order at 20 and 21. So it's possible that OKC's pick owed to the Sixers would not convey this year (if OKC wins the coin-toss).
Also, in addition to the above, if the Sixers win their final two games, the coin-toss between Utah and OKC would be for picks 19 and 20, meaning OKC's pick to the Sixers would not convey this year. This adds an interesting twist, since it's the Sixers that are owed the pick. OKC and Philly can think about whether they want the pick to convey this year or next.
BTW, the Jazz have announced that they're resting Gobert and Conley in their last game against the Spurs. They're not trying to win, it seems. They're comfortable with the 6 seed and a matchup most likely with Denver.